## § Counterexample to fundamental theorem of calculus?

- Integral of
`1/x^2`

from `[-1, 1]`

should equal `-1/x`

evaluated at `(-1, 1)`

which gives `-1/1 - (-(-1)/1)`

, that is, `-1 - 1 = -2`

. - But this is absurd since $1/x^2$ is always positive in $[-1, 1]$.
- What's going wrong?