0
. A Curve is a
differentiable map where .
f(m): M -> R
with respect to a curve c(t): I -> M
, denoted as c[f]
. g(t) = (f . c)(t) :: I -c-> M -f-> R = I -> R
.
This this is the value dg/dt(t0) = (d (f . c) / dt) (0)
.
p
: m
dimensional manifold M
, a tangent vector at a point p
is an
equivalence class of curves that have c(0) = p
, such that c1(t) ~ c2(t)
iff
:
(O, ch)
such that c1(0) ∈ O
, d/dt (ch . c1: R -> R^m) = d/dt (ch . c2: R -> R^m)
. TpM
): p
forms a vector space TpM
.
We prove this by creating a bijection from every curve to a vector R^n
.
Let (U, ch: U -> R)
be a chart around the point p
, where p ∈ U ⊆ M
. Now,
the bijection is defined as:
forward: (I -> M) -> R^n
forward(c) = d/dt (c . ch)
reverse: R^n -> (I -> M)
reverse(v)(t) = ch^-1 (tv)
TpM*
): dual space of the tangent space / Space of all linear functions from TpM
to R
. f
, there is a cotangent vector, colorfully called df
. The definition is df: TpM -> R
, df(c: I -> M) = c[f]
. That is, given a curve c
, we take the directional derivative of the function f
along the curve c
. We need to prove that this is constant for all vectors in the equivalence class and blah. push(f): TpM -> TpN
c: I -> M
, the pushforward
is the curve f . c : I -> N
. This extends to the equivalence classes
and provides us a way to move curves in M
to curves in N
, and thus
gives us a mapping from the tangent spaces.
This satisfies the identity:
push(f)(v)[g] === v[g . f]
pull(f): TpN* -> TpM*
wn : TpN -> R
, the pullback is defined as
wn . push(f) : TpM -> R
.
This satisfies the identity:
(pull wn)(v) === wn (push v)
(pull (wn : TpN->R): TpM->R) (v : TpM) : R = (wn: TpN->R) (push (v: TpM): TpN) : R