## § Counterexample to fundamental theorem of calculus?

• Integral of 1/x^2 from [-1, 1] should equal -1/x evaluated at (-1, 1) which gives -1/1 - (-(-1)/1), that is, -1 - 1 = -2.
• But this is absurd since $1/x^2$ is always positive in $[-1, 1]$.
• What's going wrong?