§
1
n
+
2
n
+
⋯
+
(
n
−
1
)
n
1^n + 2^n + \dots + (n-1)^n
1
n
+
2
n
+
⋯
+
(
n
−
1
)
n
is divisible by
n
n
n
for odd
n
n
n