scratch

§ Green's Functions

created 2022-02-03 · last edited 2022-05-30
  • Can solve Ly(x)=f(x)L y(x) = f(x)Ly(x)=f(x).
  • f(x)f(x)f(x) is called as the forcing operator.
  • LLL is a linear diffeential operator. That is, it's a differential operator lik ∂x\partial_x∂x​ or ∂t∂t\partial_t \partial_t∂t​∂t​. See that ∂t∂t\partial_t \partial_t∂t​∂t​ is linear, because ∂t∂tαf+βg=α(∂t∂tf)+β(∂t∂tg)\partial_t \partial_t \alpha f + \beta g = \alpha (\partial_t \partial_t f) + \beta (\partial_t \partial_t g)∂t​∂t​αf+βg=α(∂t​∂t​f)+β(∂t​∂t​g)
  • Video reference
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