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§ Level Set of a Continuous Function Must Be Closed

created 2021-10-31 · last edited 2022-05-30
  • Let fff be continuous, let L≡f−1(y)L \equiv f^{-1}(y)L≡f−1(y) be a level set. We claim LLL is closed.
  • Consider any sequence of points s:N→Ls: \mathbb N \to Ls:N→L. We must have f(si)=yf(s_i) = yf(si​)=ysince s(i)∈Ls(i) \in Ls(i)∈L. Thus, f(si)=yf(s_i) = yf(si​)=y for all iii.
  • By continuity, we therefore have f(lim⁡si)=lim⁡f(si)=yf(\lim s_i) = \lim f(s_i) = yf(limsi​)=limf(si​)=y.
  • Hence, lim⁡si∈L\lim s_i \in Llimsi​∈L.
  • This explains why we build Zariski the way we do: the level sets of functions must be closed. Since we wish to study polynomials, we build our topology out of the level sets of polynomials.
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